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aggiunte informazioni sezione 3.2.4
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@ -19,7 +19,7 @@
\title{Gran Compendio OLI}
\author{\href{https://github.com/meschio94/Gran-Compendio-OLI}{Meschio}}
\date{2021\\V1.0a}
\date{2021\\V1.0b}
\begin{document}
\maketitle
@ -408,9 +408,21 @@ Procediamo infine ad avere gli 0 nelle rispettive colonne della nostra base, in
\subsubsection{Duale del problema}
Come trasformiamo il nostro sistema in un problema duale ?\\
Per prima cosa dobbiamo scegliere una direzione per i segni, tutti devono andare nella stessa direzione (non va considerata la riga finale delle $x_i \geqq 0$ ), Esempio:\\
Per prima cosa dobbiamo scegliere una direzione per i segni, tutti devono andare nella stessa direzione (non va considerata la riga finale delle $x_i \geqq 0$ ), possiamo seguire questa tabella per indicazioni più rigorose:\\
\begin{center}
\raisebox{-.5\height}{\includegraphics[width=8cm]{immagini/DualeProblema0.jpg}}
\raisebox{-.5\height}{\includegraphics[width=8cm]{immagini/DualeProblema0a.jpg}}
\end{center}
\begin{itemize}
\item se i vincoli del primale sono: \textbf{$a_i^Tx \geqq b_i$},nel duale arriveremo dal basso della regione ammissibile, le slack di conseguenza saranno \textbf{non negative}. Nel duale staremo massimizzando, percui le nostre corrispettive variabili (moltiplicative) dovranno essere \textbf{non negative}.
\item se i vincoli del primale sono \textbf{$a_i^Tx \leqq b_i$},le slack dei vincoli dovranno essere \textbf{non positive}. Nel duale staremo massimizzando, percui le nostre corrispettive variabili (moltiplicative) dovranno essere \textbf{non positive}.
\item se i vincoli del primale sono \textbf{$a_i^Tx = b_i$}, le slack dei vincoli potranno avere qualsiasi valore. Le corrispondenti variabili (moltiplicative) potranno avere qualsiasi valore.
\end{itemize}
Esempio:\\
\begin{align*}
min: &2x_1 + 3x_2 + x_3 & & min:& &2x_1 + 3x_2 + x_3\\
&-x_1 + 3x_2 - 2x_3 \geqq 8 & \Rightarrow & & &-x_1 + 3x_2 - 2x_3 \geqq 8\\
@ -418,6 +430,11 @@ min: &2x_1 + 3x_2 + x_3 & & min:& &2x_1 + 3x_2 + x_3\
&x_1, x_2,x_3 \geqq 0 & & & &x_1, x_2,x_3 \geqq 0\\
\end{align*}
Possiamo sempre ricondurci alla forma canonica o standard prima di scrivere il duale:
\begin{center}
\raisebox{-.5\height}{\includegraphics[width=8cm]{immagini/DualeProblema0b.jpg}}
\end{center}
Ordiniamo il sistema per una maggiore chiarezza:\\
\begin{center}
@ -1399,7 +1416,7 @@ Soluzione:\\
Given a PLC problem with $n$ variables and $m$ constraints, a basic matrix is: (a) a collection of $m$ constraints; (b) none of the above answers.; (c) a square $m$x$m$ matrix with value 1 on the main diagonal; (d) a collection of $n-m$ columns of the constraint matrix; (e) a square submatrix of the constraint matrix, that can be inverted.
}%
}%
\\
\\/
Soluzione:\\
(B)
\end{document}

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